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10.64=4.905t^2
We move all terms to the left:
10.64-(4.905t^2)=0
We get rid of parentheses
-4.905t^2+10.64=0
a = -4.905; b = 0; c = +10.64;
Δ = b2-4ac
Δ = 02-4·(-4.905)·10.64
Δ = 208.7568
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{208.7568}}{2*-4.905}=\frac{0-\sqrt{208.7568}}{-9.81} =-\frac{\sqrt{}}{-9.81} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{208.7568}}{2*-4.905}=\frac{0+\sqrt{208.7568}}{-9.81} =\frac{\sqrt{}}{-9.81} $
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